C++实现两个超大的字符数字相加的算法
#include <iostream>
#include <string>
#include <stack>
using namespace std;
//Acts as an helper function for large numeric string addition
void deleteLeadingZeros(string& num){
//delete any starting 0's
if(num[0] == '0'){
unsigned int strtCpyIndex = 0;
strtCpyIndex = num.find_first_not_of("0");
string temp = num.substr(strtCpyIndex);
num = temp;
}
}
//adds leading 0's for the smaller string
void equalizeLength(string& num1 , string& num2, char pad = '0'){
if(num1.size() < num2.size()){
unsigned int diff = num2.size() - num1.size();
string temp;
while(diff--) //add starting zeros
temp += pad;
temp += num1;
num1 = temp;
}
else if(num2.size() < num1.size()){
unsigned int diff = num1.size() - num2.size();
string temp;
while(diff--) //add starting zeros
temp += pad;
temp += num2;
num2 = temp;
}
}
string addLargeNumbers(string num1, string num2)
{
//simple error check
if(num1.empty())
return num2;
else if(num2.empty())
return num1;
//check for valid information passed here if you want
//holds out result of addition
stack<short> addResult;
//addResult in string version
string returnResult = "";
//delete any starting 0's
//example if num1 = 001
//after the call below num = 1
deleteLeadingZeros(num1);
deleteLeadingZeros(num2);
//match size by adding in leading 0's for the smaller number
//example num1 = 100 and num2 = 50
//after the call num1 = 100 and num2 = 050
equalizeLength(num1,num2);
int lastAddElem = num1.size()- 1;
bool hasCarry = false;
short result = 0; //holds result of each integer addition
//start calculation
for(int i = lastAddElem; i >= 0; --i)
{
result = (num1[i] - '0') + (num2[i] - '0') ; //convert to decimal and add
if(result < 10 && !hasCarry)
addResult.push(result);
else
{
if(hasCarry){
result += 1; //account for the carry
hasCarry = result < 10 ? false : true;
addResult.push(result%10);
}
else
{
hasCarry = true;
addResult.push(result % 10 );
}
}
}
//check for highest bit carry
if(hasCarry)
addResult.push(result/10);
//extract data
while(addResult.size()){
returnResult += (addResult.top() + '0');
addResult.pop();
}
return returnResult;
}
int main()
{
string num1,num2;
while(true){
cout<<"Enter 2 integer for addition : ";
cin >> num1 >> num2;
cout <<num1 << "+" << num2 <<" = "<<addLargeNumbers(num1,num2)<<endl;
}
}
