python rss分析模块feedparse

通过python的feedparse模块可以很容易的分析出rss的内容

#!/usr/bin/env python
# [代码名字: Parse an RSS feed]
# [代码分类: feedparser]  
# [代码描述: Parse and iterate over the items in an RSS feed]
# [代码作者: Tim Voet <tim.voet@gmail.com>]
# [SNIPPET_DOCS: http://www.feedparser.org/docs/introduction.html]
# [代码协议: GPL]
import feedparser
feed_url = 'http://www.jonobacon.org/feed/'
f = feedparser.parse( feed_url )
print "Feed Title %s" % f.feed.title
for entry in f.entries:
    print "Title: %s" % entry.title
    print "link: %s" % entry.link
    print "Title: %s" % entry.title