ACM 1004： Let the Balloon Rise 找到颜色最多的气球

题意：给你一堆颜色的气球，让你统计处什么颜色的气球数量最多，输出该颜色。

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges’ favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you.

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters. A test case with N = 0 terminates the input and this test case is not to be processed.
Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

Sample Input

5 green red blue red red 3 pink orange pink 0

Sample Output

red pink

Author

WU, Jiazhi

Source

ZJCPC2004

代码1：

#include <stdio.h>
#include <string.h>
main(){
    int n, i, j, t, max, num[1000];
    char color[1000][16];
    while(scanf("%d", &n) != EOF){
        if(n){
            num[0]=0;
            scanf("%s", color[0]);
            for(i=1; i <n; i++){
                num[i]=0;
                scanf("%s", color[i]);
                for(j=0; j <i-1; j++)
                    if(strcmp(color[i], color[j])==0) num[i] +=1;
            }
            max=num[0];
            t=0;
            for(i=1; i <n; i++)
               if(max <num[i]) {max =num[i]; t=i;}
            printf("%s\n",color[t]);
        }
    }
}

C++代码

#include<iostream>
#include<map>
#include<string>
using namespace std;

int main()
{
	map<string,int> balloon;
	int n;
	string a;
	while(cin >> n&& n!=0)
	{
		balloon.clear();
		while(n--)
		{
			cin >> a;
			balloon[a]++;
		}
		map<string,int>::iterator it;
		int max=-100;string maxcolor;
		for (it=balloon.begin();it!=balloon.end();it++)
		{
			if((*it).second>max)
			{
				max=(*it).second;
				maxcolor=(*it).first;
			}
		}
		cout<<maxcolor<<endl;
	}
	return 0;
}

C++代码2

#include<iostream>
#include <map>
#include <string>
#include<algorithm>
using namespace std;
const int MAX=10010;
int main()
{
    //freopen("1.txt","r",stdin);
    int n;
    char col[20];
    while(cin>>n)
    {
        if(n==0) break;
        map<string,int> balloons;
        for (int i=0;i<n;i++)
        {
            cin>>col;
            balloons[col]++;
        }
        map<string,int>::iterator p,m;
        p=m=balloons.begin();
        for (p;p!=balloons.end();p++)
        {
            if(p->second > m->second) m=p;
        }
        cout<<m->first<<endl;
    }
}