C语言基础：数组作为函数参数传递演示代码
#include <stdio.h>
void show_array(int values[], int number_of_elements)
{
int i;
printf("About to display %d values\n", number_of_elements);
for (i = 0; i < number_of_elements; i++)
printf("%d\n", values[i]);
}
int main(void)
{
int scores[5] = {70, 80, 90, 100, 90};
int count[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
int small[2] = {-33, -44};
show_array(scores, 5);
show_array(count, 10);
show_array(small, 2);
return 1;
}
输出结果
About to display 5 values 70 80 90 100 90 About to display 10 values 1 2 3 4 5 6 7 8 9 10 About to display 2 values -33 -44
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