用Python实现的”石头,剪刀,布”_python

来源：http://blog.csdn.net/sun7545526/article/details/8138603
需求:设计一个”石头,剪子,布”游戏,有时又叫”Rochambeau”,你小时候可能玩过,下面是规则.你和你的对手,在同一时间做出特定的手势,必须是下面一种手势:石头,剪子,布.胜利者从
下面的规则中产生,这个规则本身是个悖论.
(a) 布包石头.
(b)石头砸剪子,
(c)剪子剪破布.在你的计算机版本中,用户输入她/他的选项,计算机找一个随机选项,然后由你
的程序来决定一个胜利者或者平手.注意:最好的算法是尽量少的使用 if 语句.
曾经实现过一个java版本的,用的思路是通过Enum分发的方式来实现,那种实现方式灵活性相对较强,但是代码量还是较多.现在正在学习python,所以用python实现了一个简单的版本,代码的数量上还是有明显的减少[本人是新手,不足请指教]:

'''
demonstrate Stone, Stainless, Paper game
Created on 2012-11-1
@author: Eric
'''
import random;
                          #elementA-->DRAW  WIN      LOST  
COMPETE_RESULT = {"Stone":["Stone", "Stainless", "Paper"],
                                "Stainless":["Stainless", "Paper", "Stone"],
                                "Paper":["Paper", "Stone", "Stainless"]};
SIGN = {0:"Stone", 1:"Stainless", 2:"Paper"}
RESULTS = {0:"DRAW", 1:"WIN", 2:"LOST"};
def rochambeauGame():
    print('''0:STONE
1:STAINLESS
2:Paper
3:quit
''');
    while True:
        userSign = input("please input your userSign number:");
        if int(userSign) in (1, 2, 3, 0):
            if userSign == 0:
                exit();
            else:
                userSignResults = COMPETE_RESULT[SIGN[int(userSign)]];
                pcSign = SIGN[int(genereteRandomPCSign())];
                print("User Sign:" + SIGN[int(userSign)] + " PC Sign:" + pcSign + " \n####result is: user " + RESULTS[userSignResults.index(pcSign)]);
        else:
            print("please input correctly order");
#generate a random number,[0,2]
def genereteRandomPCSign():
    return random.randrange(3);
if __name__ == '__main__':
    rochambeauGame();