一个滤掉C/C++风格的注释的片段
/*
* A simple code to filter the C/C++ source code.
* Copyright (c) 2007 freebsd13 <freebsd13@163.com>
*/
#include <iostream>
using namespace std;
int main()
{
char ch,ch1= 0;
while(cin.get(ch))
{
if(ch == '/')
{
cin.get(ch);
switch(ch)
{
case '/':
do{
cin.get(ch);
}while(ch!='\n');
cout<<ch;
break;
case '*':
do{
cin.get(ch);
cin.get(ch1);
cin.putback(ch1);
}while(!(ch == '*'&&ch1 == '/'));
cin.get(ch);//吃掉放回去的字符
break;
default:
cout<<'/';
cout<<ch;
}
}else
cout<<ch;
}
return 0;
}
开心洋葱 , 版权所有丨如未注明 , 均为原创丨未经授权请勿修改 , 转载请注明一个滤掉C/C++风格的注释的片段！
