﻿ ACM 1002：A + B Problem II Java代码范例_JAVA相关_开心洋葱网
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# ACM 1002：A + B Problem II Java代码范例

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Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output

For each test case, you should output two lines. The first line is “Case #:”, # means the number of the test case. The second line is the an equation “A + B = Sum”, Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2

1 2

112233445566778899 998877665544332211

Sample Output

Case 1:

1 + 2 = 3

Case 2:

112233445566778899 + 998877665544332211 = 1111111111111111110

```import java.math.BigInteger;
import java.util.Scanner;
public class Main {
public static void main(String[] args){
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int temp,flag=n;
BigInteger a,b,c;
while(n!=0)
{
a=sc.nextBigInteger();
b=sc.nextBigInteger();
temp=flag-n+1;
System.out.println("Case "+temp+":");
System.out.println(a+" + "+b+" = "+c);
n=n-1;
if(n!=0){System.out.println("");}
}
}
public static BigInteger add(BigInteger a,BigInteger b)
{
return c;
}
}
```

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